Назад Главная страница Оглавление Далее The energy of wave vortices (corrections). Опубликовано: https://www.academia.edu/34448246/Examples_of_formulas_for_energy_in_loks https://www.academia.edu/35938766/The_energy_of_wave_vortices_corrections_
Our mathematical model is that:
(1-1)
4.
All wave objects in the gukuum are described by an algebraic
task parameters of elasticity of a solid body and a
three-dimensional wave equation. When
2. Calculation of the energy of loks.
Fig.1. Figure 1 shows a fragment running around the axis Z wave. The oscillations in it are directed along the axis Z. And the wave runs around the axis Z. As will be seen from the following, the carrier frequency (in blue) is constant over the whole wave vire. However, with the distance from the axis Z the amplitude of the traveling wave changes. In addition, with the distance from the axis Z the angular velocity of the wave changes. That is, the outer layers are lagging behind the inner ones.A particular solution of the wave equation, spherical standing waves:
(1-2) This formula is obtained from a linear combination of two solutions with different Фm(φ). i,j,m - whole numbers. i=1,2,3. j=0,1,2… m=0,1,…,j; Jj(k•r) - Spherical Bessel functions of the first kind; Yj(θ,φ)
- spherical surface harmonics;
(1-3) In formulas, the quantity k. It is related only to the actual mass (energy) of the particle, and it is determined by it. This is the link between ω in the vibrational part of the solution and the radial coordinate in the Bessel function: ω=k•c, c - speed of light. In Fig. (1-1) ω=k•c – это частота синей синусоиды, «несущей» волновой частоты. Также k=1/λ , where λ – approximate size of the wave vortex. The physics is such that in each particle (in each solution), due to physical reasons, the frequency of the wave traveling along the circle and its particle size are set. Physical causes are determined by the form of the solution, and the way the solution is wound up on itself, and how the whole system stabilizes to a stable state. Also, particles have excited states. To explore this is the business of the future. This can only be observed. Thus, all further solutions and formulas are an illustration of the actual state in which all the wave vortices are located = loks = elementary particles. Since our lok is placed vertically, the following relationships hold. In the solution for the displacement vector W there is only one component WZ . Wx и Wy are equal to zero. We have:
(1-4-1) The following formulas for the transition between Cartesian and spherical coordinates:
(1-4-2) In this way:
(1-5) Next, we go for simplicity to the dimensionless length:
(1-6) According to mathematical reference books, we have a formula for the bias WZ for the first three loks (0,0), (1,0), (1,1):
(1-7) Useful formulas:
(1-8) Further, we write out the formulas for the displacements in spherical coordinates:
(1-9) We have formulas for the strain tensor in spherical coordinates:
(1-10) The total energy of the lok after all simplifications is expressed by the formula:
(1-11) Further, we calculate the elements of the strain and energy tensor for each lok separately.
Lok (0,0). For it, only two terms of the strain tensor are nonzero:
(1-12) The energy of the lok (0,0). Here the square of the strain tensor is integrated over the space. The volume element contains a factor q2 , But the law of winding the solution contains 1/q2. These factors cancel each other and simplify the integral.
(1-13) After substituting the value Q by the formula (1-8), we obtain:
(1-14) Lok (0,0) has an axial symmetry. This can be seen from the formula for the displacement, there are no angular coordinates in it. The graph of radial energy distribution and energy density has the form:
Fig.2. As can be seen from the graph, the lok (0,0) has a low density in the center, as if emptiness.
Lok (1,0). Note that here q quite different than for lok (0,0). Non-zero elements of the strain tensor:
(1-15) After integrating formula (1-11) with respect to the angular coordinates, we obtain:
(1-16) Assuming that L1=L2 , which in most cases is valid for all terrestrial materials, we obtain the following graphical dependences of the radial energy distribution and energy density:
Fig.3. As can be seen from the graph, the lok (1,0) has a high density in the center, the so-called "core". This property exists for a proton and for a neutron.
Lok (1,1). Note that here q quite different than for loks (0,0) and (1,0).Non-zero elements of the strain tensor:
(1-17) Lok (1,1) is not axisymmetric due to the presence of the dependence on φ . After integrating formula (1-11) with respect to the angular coordinates, we obtain:
(1-18) Assuming that L1=L2 , which in most cases is valid for all terrestrial materials, we obtain the following graphical dependences of the radial energy distribution and energy density:
Fig.4.
As can be seen from the graph, the lok (1,1) also has a high
density in the center, the so-called "core". This property
exists for a proton and for a neutron. Therefore, it is very
likely that the loks (1,0) and (1,1) are a proton and a
neutron. But who is who, we do not know yet. Identification
will continue in the study of the angular momentum of loks.
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